# Why the power consumed by purely capacitive circuit is zero?

**purely**inductive or a

**purely capacitive circuit**that contains reactance, (X) the current will lead or lag the voltage by exactly 90

^{o}(the phase angle) so

**power**is both stored and returned back to the source. Thus the average

**power**calculated over one full periodic cycle will be equal to

**zero**.

Moreover, what is the power factor of a pure capacitive circuit?

The **power factor** (p.f) of a **pure capacitive circuit** will be 1, because in **capacitive circuits**, **capacitors** are used, which minimizes the value of reactive **power** almost equal to zero (0). where; Apparent **power** is equal to the square root of the sum of the (Actual **Power** & Reactive **Power**).

One may also ask, what is the power consumption of purely inductive and capacitive load? here Z is impedance , for **pure inductive** , it will be jwl . this **consumed power** will do nothing usable work but will be lost in inducing magnetizing field in **inductor**. x - angle between **load** voltage and **load** current which 90 degree for **inductive** or **capacitive** hence usable **power** is zero.

Accordingly, does capacitor consume power?

Inductor or **capacitor** are such devices that **do** not **consume** any type of electric **power** for building up the fields. In practical situation, if there is no kind of utilization of electric circuit , all the **energy** will go in vain.

What is the power consumed by pure inductive circuit?

**Power** in **Pure Inductive Circuit** Hence, the average **power consumed** in a **purely inductive circuit** is zero. The average **power** in one alteration, i.e., in a half cycle is zero, as the negative and positive loop is under **power** curve is the same.