multiplication is associative so we can write (j)(j)(-j) as ((j)(j))(-j)i don't understand why (j)(j)(-j) when converted to polar form is 1∠90°. How do one get 1∠90°?
Remember the definition of j. It is the value that, when squared (multiplied by itself) yields -1.i don't understand why (j)(j)(-j) when converted to polar form is 1∠90°. How do one get 1∠90°?
Hi,i don't understand why (j)(j)(-j) when converted to polar form is 1∠90°. How do one get 1∠90°?
by Jake Hertz
by Jake Hertz
by Jake Hertz
by Jake Hertz